F(x)=2x^2-8x+8

Solution for F(x)=2x^2-8x+8 equation:

(F)=2F^2-8F+8

We move all terms to the left:

(F)-(2F^2-8F+8)=0

We get rid of parentheses

-2F^2+F+8F-8=0

We add all the numbers together, and all the variables

-2F^2+9F-8=0

a = -2; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·(-2)·(-8)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{17}}{2*-2}=\frac{-9-\sqrt{17}}{-4}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{17}}{2*-2}=\frac{-9+\sqrt{17}}{-4}
$